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12^3-3x^2=0
We add all the numbers together, and all the variables
-3x^2+1728=0
a = -3; b = 0; c = +1728;
Δ = b2-4ac
Δ = 02-4·(-3)·1728
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{20736}=144$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144}{2*-3}=\frac{-144}{-6} =+24 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144}{2*-3}=\frac{144}{-6} =-24 $
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